Factorize:
a2 – b2 –4ac + 4c2
We have,
![]()
= a2 – 2(a)(2c) + c2 – b2
= (a – c)2 – (b)2]
Now,
Using identity: a2 – b2 = (a – b)(a + b)
![]()
Hence,
The given expression can be factorized as: ![]()
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