The zeroes of the polynomial p (x) = 3x2 – 1 are
We have,
p (x) = 3x2 – 1
∴ Zeros of p (x) are:
p (x) = 0
3x2 – 1 = 0
3x2 = 1
So, x2 = ![]()
And, x = ![]()
Thus, zeros of the given polynomial are
and -![]()
Hence, option D is correct
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.