Factorize:x3 – 5x2 – x + 5

We have,= x2(x – 5) – 1(x – 5)= (x - 5)[x2 – (1)2]Now,Using identity: a2 – b2 = (a – b)(a + b)Hence,The given expression can be factorized as:

Q15 of 274 Page 64

Factorize:
x³ – 5x² – x + 5

We have,

= x²(x – 5) – 1(x – 5)

= (x - 5)[x² – (1)²]

Now,

Using identity: a² – b² = (a – b)(a + b)

Hence,

The given expression can be factorized as:

Factorize:

(a + b)³ – a – b

Factorize:

108a² –3(b – c)²

Factorize:

a² + 2ab + b² – 9c²

Factorize:

9 – a² + 2ab – b²