Factorize:

x³ + y³ – 12xy + 64

We know that,

a³ + b³ + c³ – 3abc = (a + b + c) (a² + b² + c² – ab – bc – ca)]

Using this formula, we get

= (x)³ + (y)³ + (4)³ – 3 (x) (y) (4)

= (x + y + 4) [(x)² + (y)² + (4)² – (x) (y) – (y) (4) – (4) (x)]

= (x + y + 4) (x² + y² + 16 –xy – 4y – 4x)