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Mathematics
2. Polynomials
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Q6 of 274 Page 72

Evaluate:

(i) (99)2


(ii) (998)2

(i) We know that,


(a – b)2 = a2 – 2ab + b2


Using this formula, we get


= (100 – 1)2


= (100)2 – 2(100) (1) + (1)2


= 10000 – 200 + 1


= 9801


(ii) We know that,


(a – b)2 = a2 – 2ab + b2


Using this formula, we get


= (1000 – 2)2


= (1000)2 – 2(1000) (2) + (2)2


= 1000000 – 4000 + 4


= 996004


More from this chapter

All 274 →
4

Factorize:

9x2 + 16y2 + 4z2 –24xy + 16yz – 12xz

5

Factorize:

25x2 + 4y2 + 9z2 – 20xy – 12yz + 30xz

1

Expand:

(i) (3x + 2)2


(ii) (3a – 2b)2


(iii)

2

Expand:

(i)


(ii)


(iii)

Questions · 274
2. Polynomials
1 2 3 4 4 4 5 1 2 3 4 5 1 2 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 1 2 3 4 5 6 1 2 3 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
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