Q23 of 274 Page 62

Factorize:
2x + 4y – 8xy – 1

We have,

At first we’ll take common from the expression

= 2x – 1 – 8xy + 4y

= (2x – 1) – 4y (2x – 1)

= (2x – 1) (1 – 4y)

Hence,

The given expression can be factorized as:

Factorize:

abx² + a²x + b²x + ab

Factorize:

x³ – x² + ax + x – a – 1

Factorize:

ab(x² + y²) – xy(a² + b²)

Factorize:

a² + ab(b + 1) + b³

Factorize:2x + 4y – 8xy – 1