Factorize:
x(x + y)3 – 3x2y (x + y)
We have,
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At first we’ll take common from the expression
= x (x + y) [(x + y)2 – 3xy]
= x (x + y) (x2 + y2 + 2xy – 3xy)
= x (x + y) (x2 + y2 – xy)
Hence,
The given expression can be factorized as:
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