The zeroes of the polynomial p (x) = x² + x - 6 are

We have,

p (x) = x² + x - 6

So, zero of the given polynomial can be calculated as follows:

x² + x – 6 = 0

x² + 3x – 2x – 6 = 0

x (x + 3) – 2 (x + 3) = 0

(x + 3) (x – 2) = 0

Now, x + 3 = 0

x = - 3

And, x – 2 = 0

x = 2

Hence, the zeros of the given polynomial are -3 and 2

∴ Option C is correct