If (x + 5) is a factor of p (x) = x3 – 20x + 5k, then k =?
We have,
p (x) = x3 – 20x + 5k
It is given in the question that, (x + 5) is a factor of p (x) so:
p (- 5) = 0
(- 5)3 – 20 (- 5) + 5 k = 0
- 125 + 100 + 5k = 0
- 25 + 5k = 0
5k = 25
k = ![]()
k = 5
Hence, option B is correct
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