Q33 of 274 Page 82

If where and then the value of is

We have,

= - 1

x² + y² = - xy

x² + y² + xy = 0

∴ Value of (x³ – y³) = (x – y) (x² + y² + xy)

= (x - y) × 0

= 0

Hence, option C is correct

If (x + 5) is a factor of p (x) = x³ – 20x + 5k, then k =?

3x³ + 2x² + 3x + 2 = ?

If a + b + c = 0, then a³ + b³ + c³ = ?

(x + 2) and (x – 1) are factors of (x³ + 10x² + mx + n) then