Factorize:

8a³ + 125b³ – 64c³ + 120abc

We know that,

a³ + b³ + c³ – 3abc = (a + b + c) (a² + b² + c² – ab – bc – ca)]

Using this formula, we get

= (2a)³ + (5b)³ + (-4c)³ – 3 (2a) (5b) (-4c)

= (2a + 5b - 4c) [(2a)² + (5b)² + (-4c)² – (2a) (5b) – (5b) (-4c) – (-4c) (2a)]

= (2a + 5b - 4c) (4a² + 25b² + 16c² – 10ab + 20bc + 8ca)