Q2 of 274 Page 80

Factorize:

a3 + 8b3 + 64c3 – 24abc

We know that,


a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)]


Using this formula, we get


= (a)3 + (2b)3 + (4c)3 – 3 (a) (2b) (4c)


= (a + 2b + 4c) (a2 + 4b2 + 16c2 – 2ab – 8bc – 4ac)


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Factorize:

a3 + 3a2b + 3ab2 + b3 – 8

 1

Factorize:

125a3 + b3 + 64c3 – 60abc

 3

Factorize:

1 + b3 + 8c3 – 6bc

 4

Factorize:

216 + 27b3 + 8c3 – 108bc