Factorize:

8a³ – b³ – 4ax + 2bx

We know that,

a³ - b³ = (a - b) (a² + a × b + b²)

Using this formula, we get

= 8a³ – b³ – 2x (2a – b)

= (2a)³ – (b)³ – 2x (2a – b)

= (2a – b) [(2a)² + 2a (b) + (b)²] – 2x (2a – b)

= (2a – b) (4a² + 2ab + b²) – 2x (2a – b)

= (2a – b) (4a² + 2ab + b² – 2x)