Factorize:

125 – 8x³ – 27y³ – 90xy

We know that,

a³ + b³ + c³ – 3abc = (a + b + c) (a² + b² + c² – ab – bc – ca)]

Using this formula, we get

= (5)³ + (-2x)³ + (-3y)³ – 3 (5) (-2x) (-3y)

= (5 – 2x – 3y) [(5)² + (-2x)² + (-3y)² – (5) (-2x) – (-2x) (-3y) – (-3y) (5)]

= (5 – 2x – 3y) (25 + 4x² + 9y² + 10x – 6xy + 15y)