Find ‘x’ in the following figures?

Given: In Δ PQR, m∠ Q = (3x + 16)°, m∠ R = 68° and

m∠ P = 45°

In Δ PQR,

m∠ P + m∠ Q + m∠ R = 180° (Sum of the measures of all

angles of a triangle is 180°)

⇒ 45° + (3x + 16)° + 68° = 180°

3x + 16 + 113 = 180

3x + 129 = 180

⇒ 3x = 180 – 129 (Transposing 129 to RHS)

3x = 51

⇒ x = (Transposing 3 to RHS)

x = 17

∴ The value of x is 17°.