Q11 of 80 Page 42

Two complementary angles differ by 12o, find the angles?

Let one of the angles be x°.

The two angles differ by 12°.


∴ The second angle = (x + 12)°.


The two angle are complementary angles.


The sum of two complementary angles is 90°.


According to the given condition,


x + x + 12 = 90


⇒ 2x + 12 = 90


⇒ 2x = 90 – 12 (Transposing 12 to RHS)


2x = 78


⇒ x = (Transposing 2 to RHS)


x = 39


The first angle = x = 39°.


The second angle = x + 12 = 39 + 12 = 51°.


∴ The two complementary angles are 39° and 51°.


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