Q1 of 80 Page 56

Solve the following equation.

Given equation:

Multiplying (3x + 2) and 3 on both sides, we get



3 (2x – 3) = -2 (3x + 2)


6x – 9 = -6x – 4 (Removing brackets)


6x + 6x = –4 + 9 (Transposing 6x to LHS and 9 to RHS)


12x = 5


x = (Transposing 12 to RHS)


The solution of the given equation is x = .


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