Solve the following equation.
Given equation: 
⇒ 
(LCM of 2, 3 and 6 is 6)
⇒ 4z = 8 × 6 (Transposing 6 to RHS)
4z = 48
⇒ z = 
(Transposing 4 to RHS)
z = 12
∴ The solution of the given equation is z = 12.
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