Solve the following equation:

15 (x – 1) + 4 (x + 3) = 2 (7 + x)

Given equation: 15 (x – 1) + 4 (x + 3) = 2 (7 + x)

⇒ 15x – 15 + 4x + 12 = 14 + 2x (Removing brackets)

15x + 4x – 15 + 12 = 14 + 2x

19x – 3 = 14 + 2x

⇒ 19x – 2x = 14 + 3 (Transposing 2x to LHS and 3 to RHS)

17x = 17

⇒ x = (Transposing 17 to RHS)

x = 1

∴ The solution of 15 (x – 1) + 4 (x + 3) = 2 (7 + x) is

x = 1.