If a train runs at 40 kmph it reaches its destination late by 11 minutes. But if it runs at 50 kmph it is late by 5 minutes only. Find the distance to be covered by the train.
Let the distance covered by the train be x km.
Time delay when speed is 40 kmph = 11 minutes.
Time delay when speed is 50 kmph = 5 minutes.
The difference in time for different speeds = 11 – 5
= 6 minutes.
=
hours.
We know that, speed = ![]()
∴ Time = ![]()
According to the given condition,
![]()
⇒
(LCM of 40 and 50 is 200)
![]()
⇒
(Multiplying by 200 on both sides)
⇒ x = 20
∴ The distance to be covered by the train is 20 km.
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