Q2 of 80 Page 48

Eight times of a number reduced by 10 is equal to the sum of six times the number and 4.Find the number.

Let the number be x.

Eight times of the number reduced by 10 = 8x – 10.


Sum of six times the number and 4 = 6x + 4.


According to the given condition,


8x – 10 = 6x + 4


⇒ 8x – 6x = 4 + 10 (Transposing 6x to LHS and 10 to RHS)


2x = 14


⇒ x = (Transposing 2 to RHS)


x = 7


∴ The required number is 7.


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