Solve the following equation:
3 (t – 3) = 5 (2t – 1)
Given equation: 3 (t – 3) = 5 (2t – 1)
⇒ 3t – 9 = 10t – 5 (Removing brackets)
⇒ 3t – 10t = -5 + 9 (Transposing 10t to LHS and 9 to RHS)
-7t = 4
⇒ t =
(Transposing -7 to RHS)
t = ![]()
∴ The solution of 3 (t – 3) = 5 (2t – 1) is t =
.
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