Q10 of 80 Page 45

Solve the following equation:

5 (z + 3) = 4 (2z + 1)

Given equation: 5 (z + 3) = 4 (2z + 1)

⇒ 5z + 15 = 8z + 4 (Removing brackets)


⇒ 5z – 8z = 4 – 15 (Transposing 8z to LHS and 15 to RHS)


-3z = -11


⇒ z = (Transposing -3 to RHS)


z =


∴ The solution of 5 (z + 3) = 4 (2z + 1) is z = .


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