Solve the following equation.

Given equation:

LCM of 5 and 11 is 55.

⇒ (Multiplying by 55 on both sides)

11 (7y + 2) = 5 (6y – 5)

⇒ 77y + 22 = 30y – 25 (Removing brackets)

⇒ 77y – 30y = -25 – 22 (Transposing 30y to LHS and 22

to RHS)

47y = -47

⇒ y = (Transposing 47 to RHS)

y = -1

∴ The solution of the given equation is y = -1.