What are those two numbers whose sum is 58 and difference is 28?

Let the smaller of the two numbers be x.

The difference between the two numbers is 28.

∴ The bigger number = x + 28.

The sum of the two numbers = 58.

According to the given condition,

x + (x + 28) = 58

⇒ x + x + 28 = 58

2x + 28 = 58

⇒ 2x = 58 – 28 (Transposing 28 to RHS)

2x = 30

⇒ x = (Transposing 2 to RHS)

x = 15

The smaller of the two numbers = x = 15

The bigger of the two numbers = x + 28 = 15 + 28 = 43

∴ The two numbers are whose sum is 58 and difference is 28 are 15 and 43.