Q5 of 80 Page 45

Solve the following equation:

7z + 13 = 2z + 4

Given equation: 7z + 13 = 2z + 4

⇒ 7z – 2z = 4 – 13 (Transposing 2z to LHS and 13 to RHS)


6z = -9


⇒ z = (Transposing 6 to RHS)


z =


∴ The solution of 7z + 13 = 2z + 4 is z = .


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