For each polynomial of the following polynomials, find the value of p(2), p(1) and p(0).
p(y) = (y+1) (y-1)
p(2) means substitute value 2 in the polynomial in place of variable
p(1) means substitute value 1 in the polynomial in place of variable
p(0) means substitute value 0 in the polynomial in place of variable
p(y) = (y + 1) (y-1)
the variable is y substitute it with values 2, 1 and 0 to find p(2), p(1) and p(0) respectively
p(2)
⇒ p(2) = (2 + 1)(2 – 1)
⇒ p(2) = (3)(1)
⇒ p(2) = 3
p(1)
⇒ p(1) = (1 + 1)(1 – 1)
⇒ p(1) = (2)(0)
⇒ p(1) = 0
p(0)
⇒ p(0) = (0 + 1)(0 – 1)
⇒ p(0) = (1)(-1)
⇒ p(0) = -1
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