Expand the following cubes:(3a – 2b)3

Using Identity:(x – y)3 = x3 – y3 – 3x2y + 3y2x(3a – 2b)3 = (3a)3 – (2b)3 – 3(3a)2(2b) + 3(2b)2(3a)= 27a3 – 8b3 – 54a2b + 36b2a

Q6 of 90 Page 33

Expand the following cubes:
(3a – 2b)³

Using Identity:

(x – y)³ = x³ – y³ – 3x²y + 3y²x

(3a – 2b)³ = (3a)³ – (2b)³ – 3(3a)²(2b) + 3(2b)²(3a)

= 27a³ – 8b³ – 54a²b + 36b²a

Factorize :

9x² + 4y² + 16z² – 12 xy – 16yz + 24 xz

Factorize :

Expand the following cubes:

(1 + 2x)³

Expand the following cubes:

Questions · 90

3. Polynomials

1 2 3 4 5 6 7 1 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 4 1 1 1 1 1 2 3 4 1 1 1 1 2 2 2 2 3 4 5 6 6 6 6 7 7 7 7 7 7 1 1 1 1 1 1 2 2 2 3 3 3 4 4 4 4 4 4 5 5 6 6 6 6 7 7 7 8 8 8 8 9 10 10 11 12 12