Q7 of 90 Page 33

Find the value using the suitable identities.
(999)³

(999)³ = (1000 – 1)³

Using Identity:

(x – y)³ = x³ – y³ – 3x²y + 3y²x

(999)³ = 1000³ – 1³ – 3(1000)²(1) + 3(1)²(1000)

= 1000000000 – 1 – 3000000 + 3000

= 997002999

Find the value using the suitable identities.

(98)³

Find the value using the suitable identities.

(103)³

Factorize :

x³ + 8y³ + 6x²y + 12xy²

Factorize :

27a³ – 8b³ – 54a²b + 36ab²

Questions · 90

3. Polynomials

1 2 3 4 5 6 7 1 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 4 1 1 1 1 1 2 3 4 1 1 1 1 2 2 2 2 3 4 5 6 6 6 6 7 7 7 7 7 7 1 1 1 1 1 1 2 2 2 3 3 3 4 4 4 4 4 4 5 5 6 6 6 6 7 7 7 8 8 8 8 9 10 10 11 12 12

Find the value using the suitable identities.(999)3