Factorize :27 – 125x3 – 135x + 225x2

27 – 125x3 – 135x + 225x2 = 33 – (5x)3 – 3(3)2(5x) + 3(5x)2(3)Using Identity:(x – y)3 = x3 – y3 – 3x2y + 3y2x27 – 125x3 – 135x + 225x2 = (3 – 5x)3

Q8 of 90 Page 33

Factorize :
27 – 125x³ – 135x + 225x²

27 – 125x³ – 135x + 225x² = 3³ – (5x)³ – 3(3)²(5x) + 3(5x)²(3)

Using Identity:

(x – y)³ = x³ – y³ – 3x²y + 3y²x

27 – 125x³ – 135x + 225x² = (3 – 5x)³

Factorize :

x³ + 8y³ + 6x²y + 12xy²

Factorize :

27a³ – 8b³ – 54a²b + 36ab²

Factorize :

125x³ – 64y³ – 300x²y + 240xy²

Factorize:

(i) 64a³ + 27b³

(ii) 125x³ – 8y³

Questions · 90

3. Polynomials

1 2 3 4 5 6 7 1 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 4 1 1 1 1 1 2 3 4 1 1 1 1 2 2 2 2 3 4 5 6 6 6 6 7 7 7 7 7 7 1 1 1 1 1 1 2 2 2 3 3 3 4 4 4 4 4 4 5 5 6 6 6 6 7 7 7 8 8 8 8 9 10 10 11 12 12