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3. Polynomials
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Q7 of 90 Page 33

Find the value using the suitable identities.

(98)3

(98)3 = (100 – 2)3

Using Identity:


(x – y)3 = x3 – y3 – 3x2y + 3y2x


(98)3 = 1003 – 23 – 3(100)2(2) + 3(2)2(100)


= 1000000 – 8 – 60000 + 1200


= 941192


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3. Polynomials
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