Use the factor theorem to determine whether g(x) is a factor of p(x)?
p(x) = 2x3 + x2 – 2x – 1; g(x) = 2x + 1
Substituting the g(x) = 0, we get -
2x + 1 = 0
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Now, substituting x = – 1 in p(x), we get -
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= 0
⇒ Remainder = 0
⇒ g(x)) = 2x + 1 is a factor of p(x) = 2x3 + x2 – 2x – 1.
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