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3. Polynomials
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Q8 of 90 Page 33

Factorize :

27a3 – 8b3 – 54a2b + 36ab2

27a3 – 8b3 – 54a2b + 36ab2 = (3a)3 – (2b)3 – 3(3a)2(2b) + 3(3a)(2b)2

Using Identity:


(x – y)3 = x3 – y3 – 3x2y + 3y2x


27a3 – 8b3 – 54a2b + 36ab2 = (3a – 2b)3


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All 90 →
7

Find the value using the suitable identities.

(999)3

8

Factorize :

x3 + 8y3 + 6x2y + 12xy2

8

Factorize :

27 – 125x3 – 135x + 225x2

8

Factorize :

125x3 – 64y3 – 300x2y + 240xy2

Questions · 90
3. Polynomials
1 2 3 4 5 6 7 1 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 4 1 1 1 1 1 2 3 4 1 1 1 1 2 2 2 2 3 4 5 6 6 6 6 7 7 7 7 7 7 1 1 1 1 1 1 2 2 2 3 3 3 4 4 4 4 4 4 5 5 6 6 6 6 7 7 7 8 8 8 8 9 10 10 11 12 12
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