Q1 of 90 Page 33

Using suitable identities find the products.
(x + 3)(x + 7)

Using identity -

(x + a)(x + b) = x² + (a + b)x + ab, we get -

(x + 3)(x + 7) = x² + (3 + 7)x + 3× 7

= x² + 10x + 21

Find the zeroes of the polynomials:

x³ – 3x² – 9x – 5

Find the zeroes of the polynomials:

x³ – 23x² + 142x – 120

Using suitable identities find the products.

(x – 5) (x + 8)

Using suitable identities find the products.

(2x + 7) (3x – 5)

Questions · 90

3. Polynomials

1 2 3 4 5 6 7 1 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 4 1 1 1 1 1 2 3 4 1 1 1 1 2 2 2 2 3 4 5 6 6 6 6 7 7 7 7 7 7 1 1 1 1 1 1 2 2 2 3 3 3 4 4 4 4 4 4 5 5 6 6 6 6 7 7 7 8 8 8 8 9 10 10 11 12 12

Using suitable identities find the products.(x + 3)(x + 7)