Q1 of 90 Page 31

Determine which of the following polynomials has (x – 1) a factor?

x3 – x2 – (2 + √3)x + √3

We know that (x – 1) will be the factor of the polynomial if by substituting x = 1 in polynomial we get the zero remainder

by putting x = 1 in x3 – x2 – (2 + √3)x + √3, we get -


13 – 1 – (2 + √3)1 + √3 = 1 – 1 – 2 – √ 3 + √ 3


= – 2≠0


(x – 1) is not a factor of x3 – x2 – (2 + √3)x + √3


More from this chapter

All 90 →