Determine which of the following polynomials has (x – 1) a factor?
x3 – x2 – (2 + √3)x + √3
We know that (x – 1) will be the factor of the polynomial if by substituting x = 1 in polynomial we get the zero remainder
∴ by putting x = 1 in x3 – x2 – (2 + √3)x + √3, we get -
13 – 1 – (2 + √3)1 + √3 = 1 – 1 – 2 – √ 3 + √ 3
= – 2≠0
⇒ (x – 1) is not a factor of x3 – x2 – (2 + √3)x + √3
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