Q1 of 90 Page 33

Using suitable identities find the products.
(x – 5) (x + 8)

Using identity -

(x + a)(x + b) = x² + (a + b)x + ab, we get -

(x + (– 5)) (x + 8) = x² + (– 5 + 8)x + (– 5)× 8

= x² + 3x – 40

Find the zeroes of the polynomials:

x³ – 23x² + 142x – 120

Using suitable identities find the products.

(x + 3)(x + 7)

Using suitable identities find the products.

(2x + 7) (3x – 5)

Using suitable identities find the products.

(5 – 3x) (3 + 2x)

Questions · 90

3. Polynomials

1 2 3 4 5 6 7 1 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 4 1 1 1 1 1 2 3 4 1 1 1 1 2 2 2 2 3 4 5 6 6 6 6 7 7 7 7 7 7 1 1 1 1 1 1 2 2 2 3 3 3 4 4 4 4 4 4 5 5 6 6 6 6 7 7 7 8 8 8 8 9 10 10 11 12 12

Using suitable identities find the products.(x – 5) (x + 8)