Factorize :x3 + 8y3 + 6x2y + 12xy2

x3 + 8y3 + 6x2y + 12xy2 = x3 + (2y)3 + 3x2(2y) + 3x(2y)2Using Identity:(x + y)3 = x3 + y3 + 3x2y + 3y2xx3 + 8y3 + 6x2y + 12xy2 = (x + 2y)3

Q8 of 90 Page 33

Factorize :
x³ + 8y³ + 6x²y + 12xy²

x³ + 8y³ + 6x²y + 12xy² = x³ + (2y)³ + 3x²(2y) + 3x(2y)²

Using Identity:

(x + y)³ = x³ + y³ + 3x²y + 3y²x

x³ + 8y³ + 6x²y + 12xy² = (x + 2y)³

Find the value using the suitable identities.

(103)³

Find the value using the suitable identities.

(999)³

Factorize :

27a³ – 8b³ – 54a²b + 36ab²

Factorize :

27 – 125x³ – 135x + 225x²

Questions · 90

3. Polynomials

1 2 3 4 5 6 7 1 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 4 1 1 1 1 1 2 3 4 1 1 1 1 2 2 2 2 3 4 5 6 6 6 6 7 7 7 7 7 7 1 1 1 1 1 1 2 2 2 3 3 3 4 4 4 4 4 4 5 5 6 6 6 6 7 7 7 8 8 8 8 9 10 10 11 12 12