If θ = 45°, find the value of(i) (ii) cos2 θ - sin2 θ

(i) Given θ =45°We know that,tan(45o) = 1= 1+ 2= 3(ii) cos2 θ – sin2 θGiven θ = 45°So, cos2 45° – sin2 45°= 0

Q2 of 268 Page 4

If θ = 45°, find the value of
(i)

(ii) cos² θ - sin² θ

(i)

Given θ =45°

We know that,

tan(45^o) = 1

= 1+ 2

= 3

(ii) cos² θ – sin² θ

Given θ = 45°

So, cos² 45° – sin² 45°

= 0

If cos θ +sin θ=1, prove that cos θ – sin θ = ± 1

Find the value of the following :

(i) sin 30^o + cos 60^o

(ii) sin² 45^o+cos²45^o

(iii) sin 30^o + cos 60^o – tan45^o

(iv)

(v) tan 60^o x cos30^o

Find the numerical value of the following :

sin45°.cos45° – sin²30°.

Find the numerical value of the following :