Q47 of 268 Page 4

In the given figure ABC is right angled at B and BD is perpendicular to AC. Find (i) cos θ, (ii) cot α.

Firstly, we find the value of AC

In right angled ∆ABC


(AB)2 + (BC)2 = (AC)2


⇒ (12)2 + (5)2 = (AC)2


⇒ 144+25 =(AC)2


⇒ (AC)2 =169


⇒ AC =√169


⇒ AC =±13


⇒ AC =13 [taking positive square root since, side cannot be negative]


(i)


(ii)


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