If tan θ + sec θ = x, show that sin θ= 
tan θ+ sec θ = x
⇒ tan θ = x – sec θ
Squaring both sides, we get
⇒ tan2 θ =(x – secθ)2
⇒ tan2 θ = x2 + sec2θ – 2xsec θ
⇒ sec2 θ – 1 = x2 + sec2θ – 2xsec θ [∵ 1+ tan2 A = sec2 A]
⇒ –1 – x2 = –2xsecθ
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Now,
tan θ = x – sec θ
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= RHS
Hence Proved
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