Prove the following identities :
1 – 2 cos2 θ + cos4 θ = sin4θ
Taking LHS = 1 – 2 cos2 θ + cos4 θ
We know that,
cos2 θ + sin2 θ = 1
= 1– 2 cos2 θ + (cos2 θ)2
= 1 – 2 cos2 θ + (1 – sin2 θ)2
= 1 – 2 cos2 θ +1 + sin4 θ – 2sin2θ
= 2 – 2(cos2 θ + sin2θ) + sin4 θ
= 2 – 2(1) + sin4 θ
= sin4 θ
=RHS
Hence Proved
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