Q11 of 268 Page 4

In a ∆ABC prove that


In ∆ABC,


Sum of angles of a triangle = 180°


A + B + C = 180°


⇒ B + C = 180° - A





…(2)


Taking LHS



(from eq (2))


[∵ tan (90° - θ) = cot θ]


=RHS


Hence Proved


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