If, then find the values of sin θ and cos θ.

Given:

We know that,

Let,

AB = √(m² – n²) and BC = n

In right angled ∆ABC, we have

(AB)² + (BC)² = (AC)² [by using Pythagoras theorem]

⇒ (√(m² – n²))² + (n)² = (AC )²

⇒ m² – n² + n² = (AC )²

⇒ (AC)² = (m²)

⇒ AC =√ m²

⇒ AC = ±m

⇒ AC = m [taking positive square root since, side cannot be negative]

Now, we have to find the value of cos θ and sin θ

We, know that

and