Q34 of 268 Page 4

Find the value off the following:

cosec (65° + θ) – sec (25° - θ) – tan(55° - θ) + cot(35° +θ)

cosec (65° + θ) – sec (25° - θ) – tan(55° - θ) + cot(35° +θ)

= sec {90°-(65°+θ)} – sec (25° - θ) – tan(55° - θ) + tan {90°-(35° +θ)}


[ cosec θ = sec (90° - θ) and cot θ = tan (90° - θ)]


= sec ( 90° - 65°-θ) – sec (25° - θ) – tan(55° - θ) + tan (90°- 35° - θ)


= sec (25° - θ) - sec (25° - θ) – tan(55° - θ) + tan (55° - θ)


= 0


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