Prove the followings identities:
(1 – sin θ)(1 + sin θ) = cso2 θ
Taking LHS = (1 – sinθ)(1+ sinθ)
Using identity , (a + b) (a – b) = (a2 – b2) , we get
= (1)2 – (sinθ)2
= 1 – sin2 θ
= cos2 θ [∵ cos2 θ + sin2 θ = 1]
= RHS
Hence Proved
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