Q22 of 268 Page 4

Given calculate all other trigonometric ratios.


Given:


We know that,




Let,


BC = 12k and AC = 13k


where, k is any positive integer.


In right angled ∆ABC, we have


(AB)2 + (BC)2 = (AC)2 [by using Pythagoras theorem]


(AB)2 + (12k)2 = (13k )2


(AB)2 + 144k2 = 169k2


(AB)2 = 169k2 – 144k2


(AB)2 = 25k2


AB = 25k2


AB =±5k [taking positive square root since, side cannot be negative]


Now, we have to find the value of other trigonometric ratios.


We, know that










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