Q15 of 268 Page 4

In a rectangle ABCD, BD : BC = 2 : √3, then find ∠BDC in degrees.

Given BD: BC = 2 : √3

We have to find the ∠BDC

We know that,

⇒ sin θ = sin 60^o

⇒ θ = 60^o

Show by an example that

sin A – sin B ≠ sin (A – B)

In a right hypotenuse AC = 10 cm and ∠A = 60°, then find the length of the remaining sides.

Express the following as trigonometric ratio of complementary angle of θ.

(i) cos θ (ii) sec θ

(iii) cot θ (iv) cosec θ

(v) tan θ

Express the following as trigonometric ratio of complementary angle of 90^o- θ.

(i) tan (90^o- θ)

(ii) cos (90^o- θ)