Q3 of 184 Page 10

Find the value of y for which the distance between the points P(2, - 3) and Q(10, y) is 10 units.

Given that the distance between the points P(2, - 3) and Q(10, y) is 10.



We need to find the value of y.


We know that distance(S) between the points (x1, y1) and (x2, y2) is



102 = (- 8)2 + (3 + y)2


100 = 64 + (3 + y)2


(3 + y)2 = 36


3 + y = ±6


y = 3 + 6 (or) y = 3 - 6


y = 9 (or) y = - 3


The values of y are 9, - 3.


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