Find the value of y for which the distance between the points P(2, - 3) and Q(10, y) is 10 units.
Given that the distance between the points P(2, - 3) and Q(10, y) is 10.

We need to find the value of y.
We know that distance(S) between the points (x1, y1) and (x2, y2) is ![]()
⇒ ![]()
⇒ 102 = (- 8)2 + (3 + y)2
⇒ 100 = 64 + (3 + y)2
⇒ (3 + y)2 = 36
⇒ 3 + y = ±6
⇒ y = 3 + 6 (or) y = 3 - 6
⇒ y = 9 (or) y = - 3
∴ The values of y are 9, - 3.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.