Three consecutive vertices of a rhombus are (5,3), (2,7) and (-2,4). Find the fourth vertex.

Let the coordinates of the fourth vertex D be (x, y).
We know that diagonals of a rhombus bisect each other.
∴ Midpoint of AC = Midpoint of BD …(i)
Coordinates of the midpoint of AC are
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Coordinates of the midpoint of BD are
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So, according to eq. (i), we have
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⇒ 2 + x = 3 and 7 + y = 7
⇒ x = 1 and y = 0
Thus, the coordinates of the vertex D are (1, 0)
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