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10. Coordinates Geometry
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Q15 of 184 Page 10

Find the value of P are the points (2, 1), (p, -1) and (-1, 3)collinear?

Given A(2, 1), B(p, -1) and C(-1, 3) are collinear


To find: Find the value of p


So, The given points are collinear, if are (∆ABC)=0


= Area of triangle =


Then,


= 2(-4)+p(2)-2=0


= -8 +2p -2 = 0


= 2p = 10


Hence, p =


More from this chapter

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15

Find the value of K for which the points (7, -2), (5, 1), (3, k) are collinear.

15

Find the value of K for which the points (8, 1), (k, -4), (2, -5) are collinear?

16

Show that the straight line joining the points A(0, -1) and B(15, 2) divides the line joining the points C(-1, 2)and D(4, -5) internally in the ratio 2:3.

17

Find the area of the triangle whose vertices are

((a+1) (a+2), (a+2)), ((a+2) (a+3), (a+3)) and ((a, 3) (a+4), (a+4))

Questions · 184
10. Coordinates Geometry
1 A 1 1 1 1 E 1 F 2 2 B 2 C 2 D 2 E 2 F 3 4 5 6 7 8 1 1 1 1 1 1 2 2 2 2 2 2 3 4 5 6 7 8 1 1 1 1 1 1 2 3 3 3 4 4 4 5 5 5 6 6 7 7 7 7 7 8 9 10 10 11 11 12 12 13 14 14 14 14 14 14 14 15 16 17 17 18 19 20 20 21 22 23 24 25 25 25 26 27 28 29 1 1 1 2 2 3 3 3 3 4 5 6 7 8 8 8 9 10 11 12 13 13 14 15 15 15 15 16 16 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 1 1 1 1 1 1 1 1 2 2 2 2 2 3 4 5 6 6 7 8 9 10 11 12 13 14 15 15 15 15 15 16 17 18 19 20 21 22 23 24 25 26
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